** NOTE**: Where the solution requires a process,

__, not simply the solution. Your grade in all the homework assignments and exams depends on the legibility of submission__

**show that process****typing or screen shots**preferred, ensuring that page arrangement is all the same direction orientation.

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Get Started**Convert the following between specified bases:**

a) Decimal 496.5625 to: (i) Binary, (ii) Octal & (iii) Hex

b) Binary 11010100.011 to: (i) Decimal, (ii) Octal & (iii) Hex

c) Octal 765.3 to: (i) Decimal, (ii) Binary & (iii) Hex

d) Hex C2F5.B: (i) Decimal, (ii) Binary & (iii) Octal

**2.Perform the indicated operations:**

a) Division (Binary): 1010110 / 101 (Operation uses multiplications and subtractions: obtain

quotient and remainder, showing your operations step by step.)

b) Multiplication (Binary): 1010 x 1100 (Show steps and result.)

c) Display and Logic (BCD): 0100 1000 0110 0011

(i) What decimal number does this represent

(ii) Develop a 10-row logic table to illuminate any decimal number on a 7-segment LED

{segments lettered a – g, from top-to-bottom, left-to-right}. An example the segments

illuminating a 7, 0111, would be 0 1 1 1 (left side for I3 – I0) and 1 0 1 0 0 1 0 (right side for

segments a – g). This reinforces what you’ve done in Lab 1.

3. **Using a 4-variable Karnough map, optimize the following functions and show**

**the resulting function expressed in (i) algebra and (ii) using a logic composed of AND, OR, and**

**NOT primitives:**

a) F(A, B, C, D) = Î£m(0, 2, 4, 5, 8, 10, 11, 15)

b) F(A, B, C, D) = Î£m(0, 1, 2, 4, 5, 6, 10, 11)

c) F(W, X, Y, Z) = Î£m(0, 2, 4, 7, 8, 10, 12, 13)

4. **Don’t Care. Using a Karnough map and specified don’t-care conditions d,**

**optimize the following functions and show the resulting function expressed in (i) algebra and**

**(ii) using a logic composed of AND, OR, and NOT primitives:**

a) F(A, B, C) = Î£m(3, 5, 6), d(A, B, C) = ïƒ¥m(0, 7)

b) F(W, X, Y, Z) = Î£m(0, 2, 4, 5, 8, 14, 15), d(W, X, Y, Z C) = Î£m(7, 10, 13)

c) F(A, B, C, D) = Î£m(4, 6, 7, 8, 12, 15), d(A, B, C, D) = Î£m(2, 3, 5, 10, 11, 14)

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